Question

Will someone please help me

Answer 1

The filled table for each equation by using the exact values in the table is

10x+2y=56

x y

______________________

0 28

`(56)/(10)` 0

________________________

8x+3y=49

x y

_________________________

0
`(49)/(3)`

`(49)/(8)` 0

_________________________

Explanation:

Given equations are 10x+2y=56 and 8x+3y=49

To fill the table for each equation by using the exact values in the table :

10x+2y=56

put x=0 in above equation we get

10(0)+2y=56

2y=56

`y=(56)/(2)`

`y=28`

Therefore (0,28)

put y=0 in the given equation 10x+2y=56 we get

10x+2(0)=56

10x=56

`x=(56)/(10)`

Therefore (
`(56)/(10)`,0)

10x+2y=56

x y

_________________________

0 28

`(56)/(10)` 0

__________________________

For

8x+3y=49

put x=0 in above equation we get

8(0)+3y=49

3y=49

`y=(49)/(3)`

Therefore (0,
`(49)/(3)`)

put y=0 in the given equation 8x+3y=49 we get

8x+3(0)=49

8x=49

`x=(49)/(8)`

Therefore (
`(49)/(8)`,0)

8x+3y=49

x y

_________________________

0
`(49)/(3)`

`(49)/(8)` 0

________________________