Question

Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train travels at a faster rate in by what factor?

Train A is faster by factor of .20

Train A is faster by a factor of 1.01

Train b is faster by a factor of .20

Train b is faster by a factor of 1.01

Answer 1

Train A is faster by a factor of 1.01

Explanation:

Here is what's given:

Train A has a distance of 175 miles. The time is 4 hours

Train B is y=43.5x

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line. The standard equation of the slope of the line is y = mx+b

Where m is the slope and we are given with y = 43.5x.

After comparing with the standard equation we get m = 43.5

Therefore the speed of train B is 43.5 miles per hours

Train A travels faster at a rate of 1.01 mph

Answer 2

Train A is faster by a factor of 1.01

Explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor =?

Solution:

The speed of the train A =
`(Distance)/(time)`

The speed of train A =
`(175)/(4)`

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5 miles per hours

Train A travels faster

`Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}`

`rate = (43.75)/(43.5)`

rate =1.01