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2. Confirm that 1 + V5 and 1 - V5 are the correct roots for x^2 - 2x - 4 = 0.

User ColinD
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Answer:

Explanation:


{\displaystyle \Delta =b^(2)-4ac} (for this equation b=-2 ; a=1 ; c=-4 )</strong></p><p></p><p>Δ= (-2)^2-4*(-4)*1=4+16=20</p><p>√(20) =2√(5) </p><p>x_(1)=(2+2√(5) )/(2) = (2(1+√(5)) )/(2) =1+\sqrt{5</p><p>x_(2)=(2-2√(5) )/(2) = (2(1-√(5)) )/(2) =1-\sqrt{5

User Robert Almgren
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