1 Answer

Steve Oh · Answer 1 · 2021-05-31T11:14:08+0000

The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.

Step-by-step explanation:

Electric field is the ratio of force and charge.

Electric field, E = 280000 N/C

Charge, q = -7.9 C

We have

$E=(F)/(q)\\\\280000=(F)/(7.9)\\\\F=280000* 7.9\\\\F=2.21* 10^6N$

The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.