Question

A bobsled team pushes a 132-kg bobsled. If the combined push of the team is 450.0 N and the bobsled also experiences a force of friction of 35 N, what is the acceleration of the bobsled?

Answer 1

3.14 m/s^2 is the acceleration

Step-by-step explanation:

You must use the formula Fnet=ma

So the total forces acting on the system are the 450N push force and the 35N friction force, which acts in the opposite direction.

Thus, the sum of the forces is 450 -35= 415N

Also you know the mass is 132 kg, so to find the acceleration divide the previously calculated net force by the mass

So 415/132 =3.14 m/s^2

Hope this helped:)