Question

If a barrel of oil weighs 1.5 kN, calculate the specific weight, density, and specific gravity of the oil. The barrel weighs 110 N.

Answer 1

To solve this problem we will apply the theoretical concepts and definitions given for the specific weight, density and specific gravity. Consider also that a barrel contains 159 liters or
`0.159 m^3`

Consider the net weight of the oil which would be

`W_(oil)= 1500-110`

`W_(oil)= 1390 N`

The specific weight is defined as the proportion of weight by volume thereof, therefore

`\gamma = (1390)/(0.159)`

`\gamma = 8742.14 N/m^3`

Through the information given we could find mass and density through the following relations:

Mass

`W = mg \rightarrow m = (W)/(g)`

`m= (1390)/(9.8)`

`m = 141.84 kg`

Density

`\rho = (m)/(V) \rightarrow \text{Here m is the mass and V the Volume}`

`\rho = (141.84)/(0.159)`

`\ rho = 892.05 kg/m^3`

Specific gravity,

`S= (\rho_(oil))/(\rho_(water)) \text{Her the specific gravity is the ratio between the density of the oil and the water}`

`S= (892.05)/(1000)`

`S= 0.892`