The two numbers are 15 and 6
Solution:
Let the two number be "a" and "b"
Let the first number be "a" and second number be "b"
Given that,
The difference between two numbers is 9
a - b = 9 -------- eqn 1
The first number plus twice the other number is 27
First number + twice the second number = 27
a + 2b = 27 ---------- eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
a = 9 + b ------ eqn 3
Substitute eqn 3 in eqn 2
9 + b + 2b = 27
3b = 27 - 9
3b = 18
Divide both sides of equation by 3
b = 6
Substitute b = 6 in eqn 3
a = 9 + 6
a = 15
Thus the two numbers are 15 and 6