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If n denotes a number to the left of 0 on the number line such that the square of n is less than
\small (1)/(100), then the reciprocal of n must be _________.

1 Answer

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The reciprocal of n must be less than –10

Solution:

Given n denotes a number to the left of 0 means n < 0.

Square of n is less than
(1)/(100) means
n^2<(1)/(100).

Therefore, we have
n<0 and
n^2<(1)/(100).


n^2<(1)/(100)

Taking square root on both sides, we get


n<\± (1)/(10)


(-1)/(10)<n<(1)/(10)

⇒ But we know that n < 0, so
n<(1)/(10) false.

It should be
(-1)/(10)<n.

To equal the expression, multiply both sides of the equation by –10n.


-(1)/(10) *(-10)/(n)>n *(-10)/(n) (symbol < changed to > when multiply by minus)


(1)/(n)>-10

Hence, the reciprocal of n must be less than –10.

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