Answer:
There are 64 possible birth orders in a family with six children.
Explanation:
Let's start from 1 children.
You can have M or F. So two possible birth orders.
With two children, you can have M-M, M-F, F-M, F-F. So 2^2 = 4 possible birth orders.
For three children.
M-M-M, M-M-F, M-F-M, M-F-F, F-M-M, F-M-F, F-F-M, F-F-F. So 2^3 = 8 possible birth orders.
Generalizing:
For n children, you can have
birth orders.
In this problem, we have that:
The family has 6 chilren.
So there are
possible birth orders.