Answer: 25% of the children will have both anirida and migraine headache
Explanation: The man has a dominant gene for anirida and normal headache with a mom with no blindness. Therefore, the man gene is (Nn) for heterozygous anirida and (mm) for normal headaches and his wife has heterozygous gene for migraine (Mm) 'cause her dad has normal headache and homozygous gene for normal vision(nn) .
Therefore
Nnmm × Mmnn= NnMm Nnmm Nnmm nnmm.
The crossing would give birth to Offspring with nirida and migraine (NnMm) =1/4 ×100= 25%