Question

High power lasers in factories are used to cut through cloth and metal. One such laser has a beam diameter of 0.863 mm and generates an electric field at the target having an amplitude 0.955 MV/m. The speed of light is 2.99792 × 10⁸ m/s the permeability of free space is 4π × 10⁻⁷ T· N/A. What is the amplitude of the magnetic field produced? Answer in units of T.

Answer 1

I= 12.09×10^8 W/m^2

Step-by-step explanation:

Em = amplitude of electric field = 0.955 MV/m = 0.955 x 10^6 V/m

B_m = amplitude of magnetic field = ?

c = speed of light = 2.99792 x 10^8 m/s

amplitude of magnetic field is given as

B_m = E_m /c

B_m = (0.955 x 10^6)/(2.99792 x 10^8 )

B_m = 0.00318 T

b)

intensity is given as

`I=(0.5)\epsilon* E_m^2 c`

`I=0.5(8.85*10^(-12))(0.955*10^6)^2(2.99792*10^8)`

I= 1209873759.69

I= 12.09×10^8 W/m^2

Answer 2

B_m = 3.186 x 10⁻³ T

Step-by-step explanation:

given,

diameter of the beam = 0.863 mm

Amplitude = 0.955 MV/m

speed of light = 2.99792 × 10⁸ m/s

he permeability of free space= 4π × 10⁻⁷ T· N/A

Amplitude of the magnetic field is given by

`B_m = (E_m)/(c)`

E_m is amplitude of the electric field.

`B_m = (0.955* 10^(6))/(2.99792* 10^8)`

B_m = 0.31855 x 10⁻² T

B_m = 3.186 x 10⁻³ T

The amplitude of magnetic field is equal to 3.186 x 10⁻³ T