Step-by-step explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.

d =
![([2 * 75 * (0.7+0.15+0.15) - 60 * 0.15 - 252 * 0.15 * 2])/(252)](https://img.qammunity.org/2021/formulas/physics/college/vnkis8psl3e0nyw9fzpubke5yx3islw47y.png)
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.