Question

A gardener uses a 60-N wheelbarrow to transport two bags of fertilizer weighing W = 252-N. Determine the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm. (Round the final answer to three decimal places.)

Answer 1

Step-by-step explanation:

Let us assume that the maximum allowable horizontal distance be represented by "d".

Therefore, torque equation about A will be as follows.

`60 * 0.15 + 252 * 0.15 * 2 + 252 * d = 2 * 75 * (0.7 + 0.15 + 0.15)`

d =
`([2 * 75 * (0.7+0.15+0.15) - 60 * 0.15 - 252 * 0.15 * 2])/(252)`

d = 0.409 m

Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.