214k views
4 votes
Calculate the volume in milliliters of a 0.92M nickel(II) chloride solution that contains 175. mmol of nickel(II) chloride NiCI2). Round your answer to 2 significant digits.

User Jsstuball
by
8.7k points

1 Answer

3 votes

Answer:

The volume of the solution is 190 milliliters.

Step-by-step explanation:


Molarity(M)=(n)/(V(L))

Where :

n = moles of compound

V = Volume of solution in L

M = Molarity of solution

Moles of nickel(II) chloride = n = 175 milli mol = 0.175 mol

1 milli mol = 0.001 mol

Volume of nickel(II) chloride solution = V

Molarity of the nickel(II) chloride = 0.92 M


0.92 M=(0.175 mol)/(V)


V=(0.175 mol)/(0.92 M)=0.1902 L

1 L = 1000 mL

V = 0.1902 L= 0.1902 × 1000 mL = 190.2 mL ≈ 190 mL

The volume of the solution is 190 milliliters.

User Catchergeese
by
8.3k points