Question

Calculate the volume in milliliters of a 0.92M nickel(II) chloride solution that contains 175. mmol of nickel(II) chloride NiCI2). Round your answer to 2 significant digits.

Answer 1

The volume of the solution is 190 milliliters.

Step-by-step explanation:

`Molarity(M)=(n)/(V(L))`

Where :

n = moles of compound

V = Volume of solution in L

M = Molarity of solution

Moles of nickel(II) chloride = n = 175 milli mol = 0.175 mol

1 milli mol = 0.001 mol

Volume of nickel(II) chloride solution = V

Molarity of the nickel(II) chloride = 0.92 M

`0.92 M=(0.175 mol)/(V)`

`V=(0.175 mol)/(0.92 M)=0.1902 L`

1 L = 1000 mL

V = 0.1902 L= 0.1902 × 1000 mL = 190.2 mL ≈ 190 mL

The volume of the solution is 190 milliliters.