Answer : The heat of the reaction is, 1.27 kJ/mole
Explanation :
First we have to calculate the heat released.
Formula used :

or,

where,
Q = heat = ?
m = mass of sample = 1.50 g
c = specific heat of water =

= initial temperature =

= final temperature =

Now put all the given value in the above formula, we get:


Now we have to calculate the heat of the reaction in kJ/mol.

where,
= enthalpy change = ?
Q = heat released = 0.0238 kJ
n = number of moles NH₄NO₃ =


Therefore, the heat of the reaction is, 1.27 kJ/mole