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Determine the force magnitude p required to lift one end of the 250-kg crate with the lever dolly.

1 Answer

1 vote

Answer:

224.8125 N

Step-by-step explanation:

Using the attached diagram, then we can work the answer as follows

Taking moments about 275 mm from point A


P* 1500=\frac {mg}{2}* 275mm

Where m is the mass, P is the load, g is acceleration due to gravity


P=\frac {250* 9.81* 275mm}{2* 1500mm}=224.8125 N

Determine the force magnitude p required to lift one end of the 250-kg crate with-example-1
User Ebohlman
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