Answer:
The limiting reactant is the ZnS
Step-by-step explanation:
The equation for this reaction is:
2 ZnS + 3O₂ = 2 ZnO + 2 SO₂
2 moles of zinc sulfure reacts with 3 moles of oxygen.
Then, 1.72 mol of ZnS would react with ( 1.72 .3)/2 = 2.58 moles of O₂
If we have 3.04 moles, then the oxygen is the reactant in excess.
Let's confirm, the ZnS as the limiting reactant.
3 moles of oxygen react with 2 moles of sulfure.
Then, 3.04 moles of O₂ would react with (3.04 .2) / 3 = 2.02 moles of ZnS
We have 1.72 moles of Zn S and it is not enough for the 2.02 moles that we need, for the reaction.