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What is the true solution to the equation below? 2 l n e Superscript l n 2 x Baseline minus l n e Superscript l n 10 x Baseline = l n 30 x = 30 x = 75 x = 150 x = 300

2 Answers

2 votes

Answer:

75

Explanation:

User Keeler
by
4.7k points
1 vote

Answer:

x=75

Explanation:

Solving Logarithm Equations

The natural logarithm is the inverse function of the exponential function which means


\displaystyle e^(\ln x)=x

We have this equation to solve for x


2lne^(ln2x)-lne^(10x)=ln30

Applying the above property


2ln2x-ln10x=ln30

Also knowing that


a.lnb=lnb^a

We have


ln(2x)^2-ln10x=ln30

Using the fundamental property of logarithms


\displaystyle \ln(a)/(b)=lna-lnb

We reduce:


\displaystyle \ln(4x^2)/(10x)=ln30

Taking off logarithms


\displaystyle (4x^2)/(10x)=30

Operating


\displaystyle 4x^2=30(10x)


\displaystyle 4x^2=300x

Dividing by x (assuming x different from 0)


\displaystyle 4x=300

Solving


\boxed{x=75 }

User Danilo Lemes
by
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