What is the likelihood of their child having the disease is:
A. 0%
Step-by-step explanation:
- The mother is heterozygous, thus she has an allele which is recessive and the other allele which is dominant.
- The father has no recessive allele for the gene.
- During meiosis in mother , two types of gametes will be produced. One type of gamete will have the recessive allele and the other type of gametes will have dominant allele.
- During meiosis in father, only one type of gametes will be formed which will have the dominant allele only.
- In a situation a female gamete with recessive allele is fertilized by a male gamete with dominant allele. The resulting zygote will be heterozygous.The effect of the recessive allele will be masked by the dominant allele and the child will not have the disease.
- In a situation a female gamete with the dominant allele is fertilized by a male gamete with dominant allele then the resulting zygote will be homozygous for dominant allele and obvioiusly the individual will not have the disease.
- Thus, in this case we can conclude that there is 0% chance of child having the disease.