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If the graph of an equation has a slope of 3 and passes through the point (1, -1). What is the equation?

3x + y = -2
3x + y = 2
3x - y = 4
3x - y = -4

1 Answer

4 votes

Answer: The equation has a slope of 3 and passes through the point (1,-1)

is 3 x-y=4

Explanation:

Step 1 :-

An equation having slope 'm' and passing through the point

is
y-y_(1) = m(x-x_(1) ).......(1)

Step 2:-

Now given equation slope m=3 and given point is (1,-1)

substitute these values in equation(1), we get


y-(-1)=3(x-1)

on simplification, we get


y+1 = 3 x-3


3 x-y=4

User Lorengphd
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