Answer:
25mL of active ingredient is needed to make 1 gallon of the suspension
Step-by-step explanation:
3 grams of active ingredient are needed to make 1 pint (16 ounces = 16×28.35 grams = 453.6 grams) of the suspension
Volume active ingredient needed to make 1 gallon (3.7854L = 3.7854×1000mL = 3785.4mL) = 3785.4mL × 3g/453.6g = 25mL