Question

Two canoes are touching and at rest on a lake. The occupants push away from each other in opposite directions, giving canoe 1 a speed of 0.56 m/s and canoe 2 a speed of 0.45 m/s .

If the mass of canoe 1 is 320 kg , what is the mass of canoe 2?

Answer 1

398.22 kg

Step-by-step explanation:

mass of I canoe, m1 = 320 kg

initial velocity of both the canoe = 0

final velocity of I canoe, v1 = 0.56 m/s

final velocity of II canoe, v2 = - 0.45 m/s

Let the mass of second canoe is m2.

Use conservation of momentum

momentum before push = momentum after push

0 + 0 = m1 x v1 + m2 x v2

0 = 320 x 0.56 - m2 x 0.45

m2 = 398.22 kg

Thus, the mass of second canoe is 398.22 kg.

Answer 2

398.22 kg

Step-by-step explanation:

`m_1` = Mass of canoe 1 = 320 kg

`m_2` = Mass of canoe 2

`v_1` = Velocity of canoe 1 = 0.56 m/s

`v_2` = Velocity of canoe 2 = 0.45 m/s

In this system the linear momentum is conserved

`m_1v_1=m_2v_2\\\Rightarrow m_2=(m_1v_1)/(v_2)\\\Rightarrow m_2=(320* 0.56)/(0.45)\\\Rightarrow m_2=398.22\ kg`

The mass of the second canoe is 398.22 kg