Answer:
The density of the liquid = 1278.95 kg/m³
Step-by-step explanation:
Density: This can be defined as the ratio of the mass of a body to its volume. The S.I unit of density is kg/m³.
From Archimedes principle,
R.d = Density of object/Density of liquid = Weight of object in air/Upthrust in liquid.
D₁/D₂ = W/U .......................... Equation 1
D₂ = D₁(U/W)........................ Equation 2
Where D₁ = Density of aluminum, D₂ = Density of liquid, W = weight of aluminum, U = upthrust.
m₁ = 3.8 kg, m₂ = 2.00 kg, g = 9.8 m/s²
W = m₁g = 3.8(9.8) = 37.24 N.
U = lost in weight of the aluminum = (m₁ - m₂)g = (3.8-2.0)9.8
U = 1.8(9.8) = 17.64 N.
Constant: D₁ = 2700 kg/m³
Substituting these values into equation 2
D₂ = 2700(17.64)/37.24
D₂ = 1278.95 kg/m³
Thus the density of the liquid = 1278.95 kg/m³