15 students are in each van and 51 students are in each bus
Solution:
Let "x" be the number of students in each van
Let "y" be the number of students in each bus
The senior class at High School A rented and filled 11 vans and 9 buses with 624 students
Therefore, a equation is framed as:
11 vans x number of students in each van + 9 buses x number of students in each bus = 624
![11 * x + 9 * y = 624](https://img.qammunity.org/2021/formulas/english/high-school/k6f0mc8ixyan83ztotft5f1mqraedrf1e6.png)
11x + 9y = 624 ------- eqn 1
High School B rented and filled 5 vans and 1 bus with 126 students
Therefore, a equation is framed as:
5 vans x number of students in each van + 1 buses x number of students in each bus = 126
![5 * x + 1 * y = 126](https://img.qammunity.org/2021/formulas/english/high-school/95cqrjc88xtekkmrpmaem1kiqpaiqfygyt.png)
5x + y = 126 ---------- eqn 2
Let us solve eqn 1 and eqn 2
From eqn 2,
y = 126 - 5x ------ eqn 3
Substitute eqn 3 in eqn 1
11x + 9(126 - 5x) = 624
11x + 1134 - 45x = 624
-34x = 624 - 1134
-34x = -510
34x = 510
x = 15
Substitute x = 15 in eqn 3
y = 126 - 5(15)
y = 126 - 75
y = 51
Thus 15 students are in each van and 51 students are in each bus