Question

The end of Hubbard Glacier in Alaska advances by an average of 105 feet per year.

What is the speed of advance of the glacier in

m/s

?

Answer 1

Speed of the glacier,
`v=1.0148* 10^(-6)\ m/s`

Step-by-step explanation:

Given that,

The average speed of Hubbard Glacier,
`v=105\ feet/year`

We need to find speed of advance of the glacier in m/s. As we know that,

1 meter = 3.28 feet

And

`1\ year=3.154* 10^7\ second`

Using the above conversions, we can write the value of average speed is :

`v=1.0148* 10^(-6)\ m/s`

So, the speed of advance of the glacier is
`1.0148* 10^(-6)\ m/s`. Hence, this is the required solution.