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Line that is perpendicular to y=3x-2 and passes through the point (-9,5)

User K S Nidhin
by
4.7k points

1 Answer

5 votes

Answer:

y = -1/3x + 2

Explanation:

The slopes of perpendicular lines are negative reciprocals.

The line y = 3x - 2 has slope 3.

The perpendicular line has slope -1/3.

Now we find the equation of the line that has slope -1/3 and passes through (-9, 5).

y = mx + b

y = -1/3x + b

5 = (-1/3)(-9) + b

5 = 3 + b

b = 2

The equation of the perpendicular is

y = -1/3x + 2

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