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What is the slope of the line that contains the point (13,-2) and (3,-2)

1 Answer

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The slope of the line that contains the point (13,-2) and (3,-2) is 0

Solution:

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

The slope of line is given as:


m = (y_2-y_1)/(x_2-x_1)

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)


(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

Substituting the values in formula, we get,


m = (-2-(-2))/(3-13)\\\\m = (-2+2)/(3-13)\\\\m = 0

Thus the slope of line is 0

User WhatsTheDiff
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