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P(A) = 0.7 P(A and B) = 0.21 P(B\A) =

P(A) = 0.7 P(A and B) = 0.21 P(B\A) =-example-1
User Asmodianis
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Answer:

1) Conditional probability
P(B/A)=0.3

2)
P(A and B)=0.28

Explanation:

1) Given that P(A)=0.7 and P(A and B)=0.21

To find the conditional probability :

Conditional probability
P(B/A)=(P(A and B)/(P(A)) when P(A)>0

Substitute the values P(A)=0.7 and P(A and B)=0.21 in above formula we get


P(B/A)=(0.21)/(0.7)</p><p>[tex]=0.3

Therefore
P(B/A)=0.3

Therefore the Conditional probability
P(B/A)=0.3

2) Given that P(A)=0.4 and P(B)=0.7 and also given that Events A and B are independents

To find P(A and B) :


P(A and B)=P(A)* P(B)

Substitute the values P(A)=0.4 and P(B)=0.7 in above formula we get


P(A and B)=(0.4)* (0.7)

=0.28[/tex]

Therefore
P(A and B)=0.28

User TZU
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