Answer:
1) Conditional probability

2)

Explanation:
1) Given that P(A)=0.7 and P(A and B)=0.21
To find the conditional probability :
Conditional probability
when P(A)>0
Substitute the values P(A)=0.7 and P(A and B)=0.21 in above formula we get
![P(B/A)=(0.21)/(0.7)</p><p>[tex]=0.3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5zyxb4c0qlm94jj8sywtlo6vd2wagz35in.png)
Therefore

Therefore the Conditional probability

2) Given that P(A)=0.4 and P(B)=0.7 and also given that Events A and B are independents
To find P(A and B) :

Substitute the values P(A)=0.4 and P(B)=0.7 in above formula we get

=0.28[/tex]
Therefore
