Question

A (non-aqueous ) solution is found to have a molarity of 2.50 molal and experiences a freezing point depression of 5.20 degree C. What is kf of the solvent (in degrees c/m) ?

Answer 1

Kf for the solvent is 2.08°C / m

Step-by-step explanation:

Formula for lowing point depression is:

ΔT = Kf . m

Then, the ΔT is 5.20°C and the molality is found to be, 2.50 m

5.20°C = Kf . 2.50 m

5.20°C /2.50 m = Kf → 2.08°C / m