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How many liters are there in 122 grams of Cu(NO3)2?

1 Answer

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Answer:

0.4 mL is the volume of 122 g of Cupper (II) nitrate

Step-by-step explanation:

You have to work with density, to solve the problem.

Density is the relation mass / volume

Cupper (II) nitrate density = Cupper (II) nitrate mass / Cupper (II) nitrate volume

3.05 g/mL = 122 g / Cupper (II) nitrate volume

Cupper (II) nitrate volume = 122 g / 3.05 g/mL

Cupper (II) nitrate volume = 0.4 mL

User Ranjit Jhala
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