Question

It took 1700 J of work to stretch a spring from its natural length of 2 m to a length of 6 m. Find the spring constant k.

Answer 1

212.5 N/m

Step-by-step explanation:

Work, W = 1700 J

y1 = 2 m

y2 = 6 m

y = y2 - y1 = 6 - 2 = 4 m

Let K be the spring constant.

Work done is given by

W = 1/2 Ky²

1700 = 0.5 x K x 4 x 4

K = 212.5 N/m

Thus, the spring constant is given by 212.5 N/m.