Answer:
Ry ride 34 minutes before lunch.
Explanation:
Given,
Total time Ry rode his bike = 41 min.
We have to find out how many minutes Ry ride before lunch.
Solution,
Let the number of minutes Ry ride after lunch be 'x'.
Since the question said, he rode for 1 minute less than 5 times the number of minutes he rode after lunch.
So we can frame it as;
Number of ride before lunch =
![5x-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/kqw199xi2icn311tlk36ikluvancvs5gs6.png)
Now, total time Ry rode his bike is the sum of number of ride before lunch and number of ride after lunch.
So we can frame it as;
![(5x-1)+x=41\\\\6x-1=41](https://img.qammunity.org/2021/formulas/mathematics/high-school/pu8g9hsu3i1v2gfkb15fq1xn6s0rxbni24.png)
On adding both side by '1' using addition property, we get;
![6x-1+1=41+1\\\\6x=42](https://img.qammunity.org/2021/formulas/mathematics/high-school/64g4uyrscxpnet6z7xnmgoocxeahg0gfwq.png)
Now using division property and divide both side by '6', we get;
![(6x)/(6)=(42)/(6)\\\\x=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/r1vvwnji4ca9t6uk48dn7ginhh2ff1d9z3.png)
Number of minute rode after lunch = 7 minutes.
Number of minute rode before lunch =
![5x-1=5*7-1=35-1 =34 \ minutes](https://img.qammunity.org/2021/formulas/mathematics/high-school/gocavsa5fff7h6gflzxkdc1iqk0dvticaj.png)
Hence Ry ride 34 minutes before lunch.