Answer:

Explanation:
We want to for a polynomial function whose real zeros are -2 with multiplicity 2 and 4 with multiplicity 1.
If -2 is a zero of a polynomial, then by the factor theorem, x+2 is a factor.
Since -2 has multiplicity 2, (x+2)² is a factor.
Also 4 is a zero which means x-4 is a factor.
We write the polynomial in factored form as:

We expand to get:

We expand further to get:


