Question

"35.0 g of silicon dioxide contains how many grams of oxygen? a. 32.0 b. 18.6 c. 1.88 d. 0.530"

Answer 1

b. 18.6

Step-by-step explanation:

Given that:-

Mass of silicon dioxide = 35.0 g

Molar mass of silicon dioxide = 60.08 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (35.0\ g)/(60.08\ g/mol)`

`Moles= 0.58255\ mol`

From the formula,
`SO_2` 1 mole of sulfur dioxide contains 2 moles of oxygen

So,

0.58255 mole of sulfur dioxide contains 2*0.58255 moles of oxygen

moles of oxygen = 1.1651 moles

Molar mass of oxygen = 15.999 g/mol

Mass= Moles*Molar mass =
`1.1651* 15.999\ g` = 18.6 g