Question

How fast can a 4000 kg truck travel around a 70 m radius turn without skidding if its tires share a 0.6 friction coefficient with the ground?

Answer 1

Velocity of truck will be 20.287 m /sec

Step-by-step explanation:

We have given mass of the truck m = 4000 kg

Radius of the turn r = 70 m

Coefficient of friction
`\mu =0.6`

Centripetal force is given
`F=(mv^2)/(r)`

And frictional force is equal to
`F_(frictional)=\mu mg`

For body to be move these two forces must be equal

So
`(mv^2)/(r)=\mu mg`

`v=√(\mu rg)=√(0.6* 70* 9.8)=20.287m/sec`