Question

Which are the solutions of the quadratic equation?

x2 = 7x + 4

StartFraction negative 7 minus StartRoot 65 EndRoot Over 2 EndFraction comma StartFraction negative 7 + StartRoot 65 EndRoot Over 2 EndFraction
–7, 0
StartFraction 7 minus StartRoot 65 EndRoot Over 2 EndFraction comma StartFraction 7 + StartRoot 65 EndRoot Over 2 EndFraction
7, 0

Answer 1

Answer: the answer is C.

Step-by-step explanation:got it right

Answer 2

`x_1=\frac{7+√(65)} {2}`

`x_2=\frac{7-√(65)} {2}`

Explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b\pm\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`x^(2)=7x+4`

equate to zero

`x^(2)-7x-4=0`

so

`a=1\\b=-7\\c=-4`

substitute in the formula

`x=\frac{-(-7)\pm\sqrt{-7^(2)-4(1)(-4)}} {2(1)}`

`x=\frac{7\pm√(65)} {2}`

therefore

`x_1=\frac{7+√(65)} {2}`

`x_2=\frac{7-√(65)} {2}`

StartFraction 7 minus StartRoot 65 EndRoot Over 2 EndFraction comma StartFraction 7 + StartRoot 65 EndRoot Over 2 EndFraction