Solve for the x-values of the x-intercepts of the parabola whose equation is y=x^2+5x+6.

Question

asked Jul 23, 2021 103k views

1 Answer

Flic · Answer 1 · 2021-07-28T11:52:14+0000

Answer:

$x\ values\ of\ x-intercepts\ are\ x=-2\ and\ x=-3$

Explanation:

x-intercepts: The point at which curve passes through the
x-axis that is when
y=0 .

The given curve is
y=x^2+5x+6 .

To get x-intercepts substitute
y=0 .

$x^2+5x+6=0\\\\x^2+3x+2x+6=0\\\\x(x+3)+2(x+3)=0\\\\(x+3)(x+2)=0\\\\Hence\ x=-3,\ x=-2$