Question

Solve for the x-values of the x-intercepts of the parabola whose equation is y=x^2+5x+6.

Answer 1

`x\ values\ of\ x-intercepts\ are\ x=-2\ and\ x=-3`

Explanation:

x-intercepts: The point at which curve passes through the
`x-axis` that is when
`y=0`.

The given curve is
`y=x^2+5x+6`.

To get x-intercepts substitute
`y=0`.

`x^2+5x+6=0\\\\x^2+3x+2x+6=0\\\\x(x+3)+2(x+3)=0\\\\(x+3)(x+2)=0\\\\Hence\ x=-3,\ x=-2`