Question

In a little league baseball game, the 145 g ball enters the strike zone with a speed of 14.0m/s . the batter hits the ball, and it leaves his bat with a speed of 23.0m/s in exactly the opposite direction.what is the magnitude of the impulse delivered by the bat to the ball?if the bat is in contact with the ball for 1.0ms , what is the magnitude of the average force exerted by the bat on the ball?

Answer 1

5365 N

Step-by-step explanation:

v = Final velocity = 23 m/s

u = Initial velocity = -14 m/s (opposite direction)

m = Mass of ball = 145 g

t = Time taken = 1 ms

Impulse is given by

`J=m(v-u)`

Impulse is also given by

`J=Ft`

`Ft=m(v-u)\\\Rightarrow F=(m(v-u))/(t)\\\Rightarrow F=(0.145* (23-(-14)))/(1* 10^(-3))\\\Rightarrow F=5365\ N`

The magnitude of the average force exerted by the bat on the ball is 5365 N