Answer: A. 0.4207
Explanation:
Given : The lifetime of a 2-volt non-rechargeable battery in constant use has a Normal distribution with a mean of 516 hours and a standard deviation of 20 hours.
i.e.
![\mu=516](https://img.qammunity.org/2021/formulas/mathematics/high-school/ovimvz5wepa0d941ij7shtkqk2odxjvz6x.png)
![\sigma=20](https://img.qammunity.org/2021/formulas/mathematics/high-school/b2qrn6omdpfwgsn4vbrj1j6ps2izl6n5tg.png)
Let x denotes the lifetime of a 2-volt non-rechargeable battery in constant use.
Then , the probability of batteries with lifetimes exceeding 520 hours is approximately:-
![P(X>520)=1-P(x\leq520)\\\\=1-P((x-\mu)/(\sigma)\leq(520-516)/(20))\\\\=1-P(z\leq0.2)\ \ [\because\ z=(x-\mu)/(\sigma)]\\\\ =1-0.5793\ \ [\text{By z-table}]\\\\=0.4207](https://img.qammunity.org/2021/formulas/mathematics/high-school/tmwg0a1yqguh3i011ndmzhpqebnrslnayw.png)
Hence, the proportion of batteries with lifetimes exceeding 520 hours is approximately 0.4207.
∴ Correct option is A. 0.4207