Answer:
Evelyn monthly allowance is $187.
Explanation:
Let the monthly allowance be 'x'.
Given:
Money taken with for shopping =
![(x)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ssksz1icixv0x3wc9jie13gl2q3gnrswxi.png)
Money spent of dress = $39.95
Also Given:
3/7 of the remainder on some accessories.
Money spent on accessories is equal to
times Difference of monthly allowance and Money spent of dress.
framing in equation form we get;
Money spent on accessories =
![(3)/(7)*((x)/(2)-39.95)](https://img.qammunity.org/2021/formulas/mathematics/high-school/6cuidynfc63o6bas8tlqm29mi8qxh3c06s.png)
Also Given:
Money left after shopping = $30.60
Now we know that;
Money taken with for shopping is equal to sum of Money spent of dress and Money spent on accessories and Money left after shopping.
framing in equation form we get;
![(x)/(2)=39.95+(3)/(7)((x)/(2)-39.95)+30.60\\\\(x)/(2)=39.95+(3x)/(14)- 17.12 +30.60](https://img.qammunity.org/2021/formulas/mathematics/high-school/wa98fa8cy4gjbt0nreuj5s888m6j3c80nb.png)
Combining like terms we get;
![(x)/(2)-(3x)/(14)=39.95-17.12+30.60\\\\(x)/(2)-(3x)/(14)= 53.43](https://img.qammunity.org/2021/formulas/mathematics/high-school/px3e3j8w6ve4ugyfcgxewwyg1p8qzj135s.png)
Now we will make denominator common using L.C.M
![(x* 7)/(2*7)-(3x*1)/(14*1)= 53.43\\\\(7x)/(14)-(3x)/(14)= 53.43\\\\(7x-3x)/(14)=53.43\\\\(4x)/(14)=53.43\\\\4x=53.43*14\\\\x= (53.43*14)/(4) = \$187](https://img.qammunity.org/2021/formulas/mathematics/high-school/jt2u8p55m9xjeg3q6irlezbg8tav1rhjh3.png)
Hence Evelyn monthly allowance is $187.