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If the length of the side of a square is doubled, what is the ratio of the areas of the original square to the area of the new square?

User Calynr
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1 Answer

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Answer:


(1)/(4)

Explanation:

Let 's' be the side of the original square

the length of the side of a square is doubled, so the length of the new square is 2s

Area of the original square with side length 's' is
s^2

Area of the new square with side length '2s' is
(2s)^2=4s^2

Area of the new square is 4 times the area of the original square

ratio of the areas of the original square to the area of the new square


(s^2)/(4s^2) =(1)/(4)

User HamedFathi
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