Answer with explanation:
We can write the vectors such that:
v= 3i-1j
w= 1i+2j
v-w =3i-1j-1i-2j
X= v-w = 2i-3j = <2,-3>
2v= 2(3i-1j)=6i-2j
2v+w=6i-2j+1i+2j
Y = 2v+w= 7i = <7,0>
Unit vector in direction of v =
![(<3,-1>)/(|v|)](https://img.qammunity.org/2021/formulas/mathematics/college/nvpmj2m9ncimfdtrrxwpzqu7jzo78topcf.png)
|v|=
![\sqrt{3^(2)+1^(2)} =√(10)](https://img.qammunity.org/2021/formulas/mathematics/college/p85y99y8nnifme1fkamg5od1bumi7l75v9.png)
Unit vector in direction of v =
![(<3,-1>)/(√(10) )=(3i)/(√(10))-(1j)/(√(10))](https://img.qammunity.org/2021/formulas/mathematics/college/qkrvrnbugf5vcxrvc7sqndwkriz280qy0i.png)
The sketches of v, w , v-w and 2v+w are attached.
In the graph Y is 2v+w and X is v-w