Question

Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v1=v and has mass m1=2m. Object 2 moves with speed v2=2–√v and has mass m2=m.

Answer 1

First object has greater magnitude of momentum.

Step-by-step explanation:

Given that,

Speed of first object = v

Mass of first object = 2m

Speed of second object = 2√v

Mass of second object = m

Suppose we find which object has the larger magnitude of its momentum

We need to calculate the momentum of first object

Using formula of momentum

`P=mv`

Where, m = mass of first object

v = speed of first object

Put the value into the formula

`P_(1)=2m* v`

`P_(1)=2mv`...(I)

We need to calculate the momentum of second object

Using formula of momentum

`P=mv`

Where, m = mass of second object

v = speed of second object

Put the value into the formula

`P_(2)=m* 2√(v)`

`P_(2)=m2√(v)`....(II)

On comparing equation (I) and (II)

Hence, First object has greater magnitude of momentum.