Question

Help math phys on these

Answer 1

001

Given:

v₀ = 0 m/s

v = 30.9 m/s

t = 4.6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (30.9 m/s + 0 m/s) (4.6 s)

Δx = 71.07 m

The circumference of the tire is π (0.547 m) = 1.72 m. So the number of revolutions is:

71.07 m / 1.72 m = 41.4 revolutions

002

Given:

ω₀ = 3.6π rad/s

ω = 8.8π rad/s

t = 5.0 s

Find: α

ω = αt + ω₀

(8.8π rad/s) = α (5.0 s) + (3.6π rad/s)

α = 3.3 rad/s²

003

1 rev / 365.25 days × (1 day / 24 hr) × (1 hr / 3600 s) × (2π rad/rev)

= 1.99×10⁻⁷ rad/s

Answer 2

Step-by-step explanation:

001

Given:

v₀ = 0 m/s

v = 30.9 m/s

t = 4.6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (30.9 m/s + 0 m/s) (4.6 s)

Δx = 71.07 m

The circumference of the tire is π (0.547 m) = 1.72 m. So the number of revolutions is:

71.07 m / 1.72 m = 41.4 revolutions

002

Given:

ω₀ = 3.6π rad/s

ω = 8.8π rad/s

t = 5.0 s

Find: α

ω = αt + ω₀

(8.8π rad/s) = α (5.0 s) + (3.6π rad/s)

α = 3.3 rad/s²

003

1 rev / 365.25 days × (1 day / 24 hr) × (1 hr / 3600 s) × (2π rad/rev)

= 1.99×10⁻⁷ rad/s