Question

If z varies directly with the square of x and inversely with the cube of y, when x = 8, y = 2, and z = 12, what is x when y = 1 and z = 24?

PLEASE HELP!!! :))))

Answer 1

Explanation:

it just means

z = k×x²/y³

12 = k×8²/2³ = k×64/8 = k×8

k = 12/8 = 3/2

24 = k×x²/1³ = 3/2 × x²/1 = 3/2 × x²

24/(3/2) = x²

48/3 = x²

16 = x²

x = 4 or

x = -4