Question

D(n)=
16
5
​
(2)
n−1

Answer 1

Which term is it u desire?

if i do not know i will be giving the wrong answer

Answer 2

See explanation

Explanation:

Assuming you want to find the 3rd term of the geometric progression defined explicitly by
`d(n)=165(2^(n-1))`, then we have to substitute n=3 to obtain:

`d(3)=165(2^(3-1))`

This will give us:

`d(3)=165(2^2)`

We evaluate to obtain:

`d(3)=165*4=660`