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Two identical positive charges are placed near each other. At the point halfway between the two charges:

O the electric field is zero and the potential is positive.
O the electric field is not zero and the potential is positive.
O the electric field is zero and the potential is zero.
O the electric field is not zero and the potential is zero.
O None of these statements is true.

2 Answers

4 votes

Answer:

the electric field is zero and the potential is positive.

Step-by-step explanation:

Electric field being a vector quantity results zero at a halfway between the two identical positive charges.

  • As we know the electric field lines emerge outward from a positive charge, so here in the mid-way of the charges the field lines oppose each other and cancel out.

Mathematically electric field is given as:


E=(1)/(4\pi.\epsilon_0) * (q)/(r^2)

where:


q = charge due to which electric field is present.


\epsilon_0= permittivity of free space


r= distance of observation of the electric field from the charge producing it.

  • Whereas, electric potential is a scalar quantity defined as the the work done to bring that charge from its initial point to the concerned point. It always adds up.

Mathematically:


V=(1)/(4\pi.\epsilon_0)* (q)/(r)

where:


q = charge due to which electric potential is present.


\epsilon_0= permittivity of free space


r= distance of observation of the electric potential from the charge producing it.

User Jignesh Variya
by
4.0k points
4 votes

Answer:

option A.

Step-by-step explanation:

The correct answer is option A.

We know the Electric field is a vector quantity. When we have to calculate the electric field halfway between the two positive charge resultant of both the charge will be the opposite direction hence, the sum of the electric field will be zero.

Whereas potential energy is the scalar quantity at half the result will add up and the potential energy will be positive.