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Given is a linear Equation 1 in the format of y = mx + b.

Equation 1, y = 46,888 + 0.78x

Plot Equation 1 on a graph paper. Label all axes and markers on the graph.

User Snake
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1 Answer

5 votes

Answer: The graph is attached.

Explanation:

The equation of a line in Slope-Intercept form is:


y=mx+b

Where "m" is the slope and "b" is the y-intercept.

In order to graph the given line, you can find the x-intercept and the y-interecept.

Knowing that the equation of that line in Slope-Intercept form is:


y = 46,888 + 0.78x

You can identify that the slope of the line is:


m= 0.78

And the y-intercept is:


b=46,888

The line intersects the x-axis when
y=0, then, substituting this into the equation and solving for "x", you get that the x-intercept is:


0 = 46,888 + 0.78x\\\\-46,888=0.78x\\\\(-46,888)/(0.78)=x\\\\x=-60,112.82

Therefore, knowing that the line passes trough the points
(0,\ 46,888)and
(-60,112.82\ ,0) you can graph it.

The graph is attached.

Given is a linear Equation 1 in the format of y = mx + b. Equation 1, y = 46,888 + 0.78x-example-1
User Lukas Petr
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3.6k points