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A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght

1 Answer

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Answer:
(17)/(2)m^2+m-5

Explanation:

By definition, the perimeter of a rectangle is:


P=2l+2w

Where "l" is the lenght and "w" is the width.

If you solve for "l":


P-2w=2l\\\\l=(P-2w)/(2)

In this case, you know that the following expression represents the perimeter of the rectangle:


19m^2+2m-10

And the width of that rectanle is represented wih this expression:


m^2

Therefore, based on the explained above, you can conclude that the lenght of that rectangle is given by:


(19m^2+2m-10-2(m^2))/(2)

Finally, simplifying the expression, you get:


=(17m^2+2m-10)/(2)=(17)/(2)m^2+m-5

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