Question

A 7.45 nC charge is located 1.66 m from a 4.22 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.(b) Is the force attractive or repulsive?i. attractiveii. repulsive

Answer 1

a.
`F=1.03* 10^(-7)N`

b.Repulsive

Step-by-step explanation:

We are given that

`q_1=7.45nC=7.45* 10^(-9)C`

`1nC=10^(-9)C`

`q_2=4.22nC=4.22* 10^(-9)C`

r=1.66m

We know that

Electrostatic force =
`F=k(q_1q_2)/(r^2)`

r=Distance between
`q_1\;and\;q_2`

k=Constant=
`9* 10^9Nm^2C^(-2)`

Using the formula

a.The magnitude of the electrostatic force=
`F=(9* 10^9* 7.45* 10^(-9)* 4.22* 10^(-9))/((1.66)^2)`

The magnitude of the electrostatic force=
`F=1.03* 10^(-7)N`

b.Both charge are positive .We know that when like charges repel each other and unlike charges attract to each other.

Therefore, the force between given charges is repulsive.