Question

If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/goC)

Thank you!

Answer 1

10.21°C

Step-by-step explanation:

From the question,we are given;

• Quantity of heat = 32,000 Joules
• Mass of water = 750 g
• Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

• We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
• That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

= 32,000 J ÷ (750× 4.18 J/g°C)

= 10.21°C

Therefore, the change in temperature is 10.21°C